*A 12 kg rock is accelerated 3 m/s*^{2}. How much force caused this?

Step 1: variables

Which of the following is correct?- 12 kg = m

3 m/s^{2}= a

F = ? - 12 kg = a

3 m/s^{2}= m

F = ? - 12 kg = m

3 m/s^{2}= S

F = ? - 12 kg = a

3 m/s^{2}= S

F = ?

- 12 kg = m
*A 12 kg rock is accelerated 3 m/s*^{2}. How much force caused this?

Step 1: Variables

12 kg = m

3 m/s^{2}= a

F = ?

Step 2: Formula

Which of the following is the formula we will use for this problem?- F = ma
- a = F/m
- S = D/T
- p = mv

*A 12 kg rock is accelerated 3 m/s*^{2}. How much force caused this?

Step 1: Variables

12 kg = m

3 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

Which of the following is correct?- F = (12kg)(3m/s
^{2}) - 12kg = m(3m/s
^{2}) - F = (12kg)/(3m/s
^{2}) - F = (12kg) + (3m/s
^{2})

- F = (12kg)(3m/s
*A 12 kg rock is accelerated 3 m/s*^{2}. How much force caused this?

Step 1: Variables

12 kg = m

3 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

F = (12kg)(3m/s^{2})

Step 4: Calculate and answer

Which of the following is correct?- F = 36 N
- F = 15 N
- F = 4 N
- F = 36 kgm/s

*A force pulls on a 20 kg sled. The sled accelerates 4 m/s*^{2}. How big was the force?

Step 1: variables

Which of the following is correct?- 20 kg = m

4 m/s^{2}= a

F = ? - 20 kg = a

4 m/s^{2}= m

F = ? - 20 kg = m

4 m/s^{2}= S

F = ? - 20 kg = a

4 m/s^{2}= S

F = ?

- 20 kg = m
*A force pulls on a 20 kg sled. The sled accelerates 4 m/s*^{2}. How big was the force?

Step 1: Variables

20 kg = m

4 m/s^{2}= a

F = ?

Step 2: Formula

Which of the following is the formula we will use for this problem?- F = ma
- a = F/m
- S = D/T
- p = mv

*A force pulls on a 20 kg sled. The sled accelerates 4 m/s*^{2}. How big was the force?

Step 1: Variables

20 kg = m

4 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

Which of the following is correct?- F = (20kg)(4m/s
^{2}) - 20kg = m(4m/s
^{2}) - F = (20kg)/(4m/s
^{2}) - F = (20kg) + (4m/s
^{2})

- F = (20kg)(4m/s
*A force pulls on a 20 kg sled. The sled accelerates 4 m/s*^{2}. How big was the force?

Step 1: Variables

20 kg = m

4 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

F = (20kg)(4m/s^{2})

Step 4: Calculate and answer

Which of the following is correct?- F = 80 N
- F = 24 N
- F = 5 N
- F = 8 kgm/s

*A 4 kg rock is moved by a force and ends up speeding up at the rate of 7 m/s*^{2}. How much force was applied to the rock?

Step 1: variables

Which of the following is correct?- 4 kg = m

7 m/s^{2}= a

F = ? - 4 kg = a

7 m/s^{2}= m

F = ? - 4 kg = m

7 m/s^{2}= S

F = ? - 4 kg = a

7 m/s^{2}= S

F = ?

- 4 kg = m
*A 4 kg rock is moved by a force and ends up speeding up at the rate of 7 m/s*^{2}. How much force was applied to the rock?

Step 1: variables

4 kg = m

7 m/s^{2}= a

F = ?

Step 2: Formula

Which of the following is the formula we will use for this problem?- F = ma
- a = F/m
- S = D/T
- p = mv

*A 4 kg rock is moved by a force and ends up speeding up at the rate of 7 m/s*^{2}. How much force was applied to the rock?

Step 1: variables

4 kg = m

7 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

Which of the following is correct?- F = (4kg)(7m/s
^{2}) - 4kg = m(7m/s
^{2}) - F = (4kg)/(7m/s
^{2}) - F = (4kg) + (7m/s
^{2})

- F = (4kg)(7m/s
^{2}. How much force was applied to the rock?

Step 1: variables

4 kg = m

7 m/s^{2}= a

F = ?

Step 2: Formula

F = ma

Step 3: Put in numbers

F = (4kg)(7m/s^{2})

Step 4: Calculate and answer

Which of the following is correct?- F = 28 N
- F = 28 kgm
- F = 28 m/s
- F = 28 sec